x^2-4x-220=0

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Solution for x^2-4x-220=0 equation:



x^2-4x-220=0
a = 1; b = -4; c = -220;
Δ = b2-4ac
Δ = -42-4·1·(-220)
Δ = 896
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{896}=\sqrt{64*14}=\sqrt{64}*\sqrt{14}=8\sqrt{14}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-8\sqrt{14}}{2*1}=\frac{4-8\sqrt{14}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+8\sqrt{14}}{2*1}=\frac{4+8\sqrt{14}}{2} $

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